The Lemon Fool

AiY & Dod can complete a job in 2hrs

AiY & IAAG can complete the same job in 3hrs

Dod & IAAG can complete the same job in 4hrs

How long will it take to do the job if all 3 work together

AiY

If this is about that duvet cover....

AsleepInYorkshire wrote:AiY & Dod can complete a job in 2hrs

AiY & IAAG can complete the same job in 3hrs

Dod & IAAG can complete the same job in 4hrs

How long will it take to do the job if all 3 work together

Depends on the job.

(e.g. cut down a tree with a two-handed saw)

Scott.

AsleepInYorkshire wrote:
AiY & Dod can complete a job in 2hrs

AiY & IAAG can complete the same job in 3hrs

Dod & IAAG can complete the same job in 4hrs

How long will it take to do the job if all 3 work together

(AiY + Dod) = 2
(AiY + IAAG) = 3
(Dod + IAAG) = 4

AiY + Dod + AiY + IAAG + Dod + IAAG = 2 + 3 + 4

2(AiY) + 2(Dod) + 2(IAAG) = 9

AiY + Dod + IAAG = 9/2

AiY + Dod + IAAG = 4.5 Hours.

Cheers,

Itsallaguess

Itsallaguess wrote:(AiY + Dod) = 2
(AiY + IAAG) = 3
(Dod + IAAG) = 4

AiY + Dod + AiY + IAAG + Dod + IAAG = 2 + 3 + 4

2(AiY) + 2(Dod) + 2(IAAG) = 9

AiY + Dod + IAAG = 9/2

AiY + Dod + IAAG = 4.5 Hours.

Probably true


Julian F. G. W.

AsleepInYorkshire wrote:AiY & Dod can complete a job in 2hrs

AiY & IAAG can complete the same job in 3hrs

Dod & IAAG can complete the same job in 4hrs

Spoiler:
AiY & Dod can do the job six times in 12 hours.
AiY's clone and IAGG can do the job four times in 12 hours.
Dod's clone and IAGG's clone can do the job three times in 12 hours.

All six can do the job 6+4+3 = 13 times in 12 hours.
Get rid of the clones and it will take 24 hours to do the job 13 times.
It will take the three originals 24/13 = ~1.846 hours = ~1 hour 50 minutes, 46 seconds.


Julian F. G. W.

jfgw wrote:

Itsallaguess wrote:
(AiY + Dod) = 2
(AiY + IAAG) = 3
(Dod + IAAG) = 4

AiY + Dod + AiY + IAAG + Dod + IAAG = 2 + 3 + 4

2(AiY) + 2(Dod) + 2(IAAG) = 9

AiY + Dod + IAAG = 9/2

AiY + Dod + IAAG = 4.5 Hours.

Probably true

I obviously left out the key element that AiY didn't disclose in his original paper, which covers the 'chatterbox coefficient', which clearly comes into play at some point in the above triple-manned theory...

Cheers,

Itsallaguess

AsleepInYorkshire wrote:AiY & Dod can complete a job in 2hrs

AiY & IAAG can complete the same job in 3hrs

Dod & IAAG can complete the same job in 4hrs

How long will it take to do the job if all 3 work together

AiY

If x is the quantity of work required to complete the job, and A, I, D is the quantity work each of the respective workers contribute in an hour

A + D = 1/2x
A + I = 1/3x
D + I = 1/4x

2A + 2D + 2I = 1/2x + 1/3x + 1/4x = 13/12x

A , D and I together provide 13/24x units an hour

Therefore the job takes 24/13 hours, about 1 hour and 41 minutes

malkymoo wrote:Therefore the job takes 24/13 hours, about 1 hour and 41 minutes

24/13ths of an hour is 2/13ths of an hour short of 26/13 = 2 hours. 2/13ths of an hour is a bit less than 2/12ths = 1/6th of an hour, i.e. 10 minutes. So 24/13ths of an hour is a bit over 1 hour and 50 minutes...

Typo?

Gengulphus

Itsallaguess wrote:

AsleepInYorkshire wrote:
AiY & Dod can complete a job in 2hrs

AiY & IAAG can complete the same job in 3hrs

Dod & IAAG can complete the same job in 4hrs

How long will it take to do the job if all 3 work together

(AiY + Dod) = 2
(AiY + IAAG) = 3
(Dod + IAAG) = 4

AiY + Dod + AiY + IAAG + Dod + IAAG = 2 + 3 + 4

2(AiY) + 2(Dod) + 2(IAAG) = 9

AiY + Dod + IAAG = 9/2

AiY + Dod + IAAG = 4.5 Hours.

Cheers,

Itsallaguess

Sorry that's incorrect. Logic dictates that all three working together would take less than any two. So the answer must be less than 2hrs (Duvet or not)

AiY

malkymoo wrote:

AsleepInYorkshire wrote:AiY & Dod can complete a job in 2hrs

AiY & IAAG can complete the same job in 3hrs

Dod & IAAG can complete the same job in 4hrs

How long will it take to do the job if all 3 work together

AiY

If x is the quantity of work required to complete the job, and A, I, D is the quantity work each of the respective workers contribute in an hour

A + D = 1/2x
A + I = 1/3x
D + I = 1/4x

2A + 2D + 2I = 1/2x + 1/3x + 1/4x = 13/12x

A , D and I together provide 13/24x units an hour

Therefore the job takes 24/13 hours, about 1 hour and 41 minutes

Correct

AiY

Gengulphus wrote:

malkymoo wrote:Therefore the job takes 24/13 hours, about 1 hour and 41 minutes

24/13ths of an hour is 2/13ths of an hour short of 26/13 = 2 hours. 2/13ths of an hour is a bit less than 2/12ths = 1/6th of an hour, i.e. 10 minutes. So 24/13ths of an hour is a bit over 1 hour and 50 minutes...

Typo?

Gengulphus

Yes that's also correct. The answer is as you say just over 1hr and 50 minutes. But look it's Christmas and I felt if malkymoo could do the job 10 minutes quicker I'd still pay for 1hr 50 minutes hence giving a small bonus. Sheesh any minute now Uncle E will be along to slap my Yorkshire wallet again

AiY

AsleepInYorkshire wrote:

Itsallaguess wrote:

AsleepInYorkshire wrote:AiY & Dod can complete a job in 2hrs

AiY & IAAG can complete the same job in 3hrs

Dod & IAAG can complete the same job in 4hrs

How long will it take to do the job if all 3 work together

(AiY + Dod) = 2
(AiY + IAAG) = 3
(Dod + IAAG) = 4

AiY + Dod + AiY + IAAG + Dod + IAAG = 2 + 3 + 4

2(AiY) + 2(Dod) + 2(IAAG) = 9

AiY + Dod + IAAG = 9/2

AiY + Dod + IAAG = 4.5 Hours.

Sorry that's incorrect. Logic dictates that all three working together would take less than any two. So the answer must be less than 2hrs (Duvet or not)

Itsallaguess's 'chatterbox coefficient' overrides logic - in particular, when all three are present, conversations between them reach critical mass, badly distracting all of them from the job in hand...

And if I were present as well, the time taken might well become infinite! ;-)

Gengulphus

Gengulphus wrote:

AsleepInYorkshire wrote:

Itsallaguess wrote:
(AiY + Dod) = 2
(AiY + IAAG) = 3
(Dod + IAAG) = 4

AiY + Dod + AiY + IAAG + Dod + IAAG = 2 + 3 + 4

2(AiY) + 2(Dod) + 2(IAAG) = 9

AiY + Dod + IAAG = 9/2

AiY + Dod + IAAG = 4.5 Hours.

Sorry that's incorrect. Logic dictates that all three working together would take less than any two. So the answer must be less than 2hrs (Duvet or not)

Itsallaguess's 'chatterbox coefficient' overrides logic - in particular, when all three are present, conversations between them reach critical mass, badly distracting all of them from the job in hand...

And if I were present as well, the time taken might well become infinite! ;-)

Gengulphus

When first presented with the question I actually worked it out the same way as IAAG I hate to brag but am reasonably sure my chatterbox coefficient approaches dizzying heights frequently. However, if the job is going to take as long as you suggest I better bring some more tea bags

AiY

Working alone,

AiY can do the job 7 times in 24 hours;
Dod can do the job 5 times in 24 hours;
IAAG can only do the job once in 24 hours.

I hope IAAG isn't being paid by the hour!


Julian F. G. W.

AsleepInYorkshire wrote:

Itsallaguess wrote:

AsleepInYorkshire wrote:
AiY & Dod can complete a job in 2hrs

AiY & IAAG can complete the same job in 3hrs

Dod & IAAG can complete the same job in 4hrs

How long will it take to do the job if all 3 work together

(AiY + Dod) = 2
(AiY + IAAG) = 3
(Dod + IAAG) = 4

AiY + Dod + AiY + IAAG + Dod + IAAG = 2 + 3 + 4

2(AiY) + 2(Dod) + 2(IAAG) = 9

AiY + Dod + IAAG = 9/2

AiY + Dod + IAAG = 4.5 Hours.

Sorry that's incorrect.

Logic dictates that all three working together would take less than any two. So the answer must be less than 2hrs (Duvet or not)

The chatterbox-coefficient -

Dod asks AiY to give a detailed run-down of the Boeing saga....

AiY asks IAAG to clearly explain his HYPTUSS bugs (2010 to 2020) and the solutions (eventually..) delivered for them...

IAAG asks Dod to give a clear and precise run-down of IT's, and their use (and abuse!!) of the term 'Revenue Reserve', and other popular, but regularly misunderstood accounting conventions...

Less than 2 hours?

Ha!

What's the time-efficiency equivalent of 'We're gonna need a bigger boat...' ?

Cheers,

Itsallaguess

jfgw wrote:
Working alone,

AiY can do the job 7 times in 24 hours;
Dod can do the job 5 times in 24 hours;
IAAG can only do the job once in 24 hours.

I hope IAAG isn't being paid by the hour!

I'm obviously very disturbed by the lack of the word 'quality' being mentioned anywhere at all in the work-based assessments carried out so far...

If you want me to just toss more of them out, just ask, but so long as you clearly understand that they'll end up looking like the ones that Bodgit and Scarper are producing, that's all...

Cheers,

Itsallaguess

Gengulphus wrote:

malkymoo wrote:Therefore the job takes 24/13 hours, about 1 hour and 41 minutes

24/13ths of an hour is 2/13ths of an hour short of 26/13 = 2 hours. 2/13ths of an hour is a bit less than 2/12ths = 1/6th of an hour, i.e. 10 minutes. So 24/13ths of an hour is a bit over 1 hour and 50 minutes...

Typo?

Gengulphus

No, I managed to come up with 111 minutes, then failed with the simple task of converting to hours and minutes!

jfgw wrote:Working alone,

AiY can do the job 7 times in 24 hours;
Dod can do the job 5 times in 24 hours;
IAAG can only do the job once in 24 hours.

I hope IAAG isn't being paid by the hour!


Julian F. G. W.

Is there a YouTube for this sort of activity?

RC

AsleepInYorkshire wrote:Sorry that's incorrect. Logic dictates that all three working together would take less than any two. So the answer must be less than 2hrs (Duvet or not)

Clearly you have never heard of Brooks's Law.

The fastest way for the three of you to complete the job is to immediately send Dod and IAAG to the pub, where you join them 30 minutes later with the job complete.